Solveeit Logo

Question

Physics Question on potential energy

An electric charge 103μC10^{-3} \mu C is placed at the origin (0,0)(0,0) of XYX-Y coordinate system. Two points AA and BB are situated at (2,2)(\sqrt{2}, \sqrt{2}) and (2,0)(2,0) respectively. The potential difference between the points AA and BB will be

A

4.5V

B

9V

C

zero

D

2V

Answer

zero

Explanation

Solution

The correct answer is C:Zero
First we have to find out the distance of point A and B from origin;
For point A: OA=(2)2+(2)2O A=\sqrt{(\sqrt{2})^{2}+(\sqrt{2})^{2}}
OA=2=r1O A=2=r_{1}
and for point B: OB=2=r2O B=2=r_{2}
The potential difference between the point AA and BB will be
VAVB=q4πε0r1q4πε0r2V_{A}-V_{B}=\frac{q}{4 \pi \varepsilon_{0} r_{1}}-\frac{q}{4 \pi \varepsilon_{0} r_{2}}
VAVB=0V_{A}-V_{B}=0 (zero)