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Question

Question: An electric bulb of 100 W is designed to operate on 220 V. Resistance of the filament is...

An electric bulb of 100 W is designed to operate on 220 V. Resistance of the filament is

A

484 Ω

B

100 Ω

C

22000 Ω

D

242 Ω

Answer

484 Ω

Explanation

Solution

By using P=V2RR=V2P=(220)2100=484ΩP = \frac{V^{2}}{R} \Rightarrow R = \frac{V^{2}}{P} = \frac{(220)^{2}}{100} = 484\OmegaSSS