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Question

Mathematics Question on Probability

An electric bulb manufacturing company manufactures three types of electric bulbs A, B and C. In a room containing these three types of electric bulbs, it is known that 6% of type A electric bulbs are defective, 4% of type B electric bulbs are defective and 2% of type C electric bulbs are defective. An electric bulb is selected at random from a lot containing 50 type A electric bulbs,30 type B electric bulbs and 20 type C electric bulbs. The selected electric bulb is found to be defective. Then the probability that the selected electric bulb was type A is

A

223\frac{2}{23}

B

23500\frac{23}{500}

C

1223\frac{12}{23}

D

1523\frac{15}{23}

E

6115\frac{6}{115}

Answer

1523\frac{15}{23}

Explanation

Solution

The correct option is (D): 1523\frac{15}{23}