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Question

Science Question on Electric Power

An electric bulb is rated 220 V and 100 W. When it is operated on 110 V, the power consumed will be –

A

100 W

B

75 W

C

50 W

D

25 W

Answer

25 W

Explanation

Solution

Energy consumed by bulb š‘ƒ=š‘‰2Rš‘ƒ=\frac {š‘‰^2}{R}
āŸ¹š‘…=š‘‰2Pš‘… = \frac {š‘‰^2}{P}
Here, V=220Ā VV = 220 \ V and P=100Ā WP = 100\ W
š‘…=(220)2100š‘… = \frac {(220)^2}{100}
R=484 ΩR = 484\ Ω
The resistance of the bulb remains constant if the supply voltage is reduced to 110V110 V. If the bulb is operated on 110V110 V, then the energy consumed by it is given by the expression for power
š‘ƒ=š‘‰2Rš‘ƒ = \frac {š‘‰^2}{R}

P=(110)2484P= \frac {(110)^2}{484}

P=12100484P= \frac {12100}{484}

P=25Ā š‘ŠP= 25 \ š‘Š

Hence, the correct option is (D): 25Ā W25\ W