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Question

Physics Question on Ray optics and optical instruments

An effective power of a combination of 5 identical convex lenses which are kept in contact along the principal axis is 25 D. Focal length of each of the convex lens is :

A

20 cm

B

50 cm

C

500 cm

D

25 cm

Answer

20 cm

Explanation

Solution

Total Power of Lenses in Contact:
When lenses are kept in contact, the effective power PeqP_{eq} is the sum of the individual powers of each lens:
Peq=PiP_{eq} = \sum P_i

Given that there are 5 identical lenses and the total power is 25 D, we have:
5P=25    P=255=5D5P = 25 \implies P = \frac{25}{5} = 5 \, \text{D}
where PP is the power of each individual lens.

Calculate the Focal Length:
The focal length ff of a lens is related to its power PP by:
P=1fP = \frac{1}{f}
where ff is in meters if PP is in diopters (D).

Therefore:
f=1P=15=0.2m=20cmf = \frac{1}{P} = \frac{1}{5} = 0.2 \, \text{m} = 20 \, \text{cm}

Conclusion:
The focal length of each convex lens is 20 cm.