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Physics Question on Waves

An carthquake gencrates both transverse (S)(S) and longitudinal (P)(P) sound waves in the earth. The spced of SS waves is about 4.5km/s4.5 \,km / s and that of PP waves is about 8.0km/s8.0 \,km / s. A scismograph records PP and SS wavcs from an carthquake. The first PP wave arrives 4.0min4.0\, min before the first SS wave. The cpicentre of the earthquake is located at a distance about

A

25 km

B

250 km

C

2500 km

D

5000 km

Answer

2500 km

Explanation

Solution

Velocity of the SS waves is v1=4.5km/sv_{1}=4.5 \,km / s.
The velocity of the PP waves is v2=8.0km/sv_{2}=8.0 \,km / s.
Let the time taken by the SS and PP waves to reach the
seismograph be t1t_{1} and t2.t_{2} . It is given that
t1t2=4min=4×60=240sect _{1}- t _{2}=4 min =4 \times 60=240\, sec \ldots (i)
Let the distance of the epicentre (km)( km ) be SS. Then
S=v1t1=v2t2S = v _{1} t _{1}= v _{2} t _{2}
4.5×t18t2=0\Rightarrow 4.5 \times t_{1}-8 t_{2}=0
t2=.4.58t1\Rightarrow t_{2}=.4 .58 t_{1} \ldots (ii)
Using (i) and (ii)
t1t2=240t_{1}-t_{2}=240
t1(14.58)=240\Rightarrow t_{1}\left(1-\frac{4.5}{8}\right)=240
t1=240×835=548.5s.\Rightarrow t_{1}=\frac{240 \times 8}{35}=548.5\, s .
S=v1t1=4.5×548.5\therefore S=v_{1} t_{1}=4.5 \times 548.5
=2468.62500km.=2468.6 \approx 2500\, km .