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Question: An average induced e.m.f. of 1V appears in a coil when the current in it is changed from 10A in one ...

An average induced e.m.f. of 1V appears in a coil when the current in it is changed from 10A in one direction to 10 A in opposite direction in 0.5 sec. Self-inductance of the coil is

A

25 mH

B

50 mH

C

75 mH

D

100 mH

Answer

25 mH

Explanation

Solution

∣e∣=Ldidt⇒1=L×{10−(−10)}0.5⇒L=25mH| e | = L \frac { d i } { d t } \Rightarrow 1 = \frac { L \times \{ 10 - ( - 10 ) \} } { 0.5 } \Rightarrow L = 25 \mathrm { mH }