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Question: An automobile engine develops 100 Kw when rotating at a speed of 1800 rpm. The torque delivered by t...

An automobile engine develops 100 Kw when rotating at a speed of 1800 rpm. The torque delivered by the engine is

A

1026πNm\frac { 10 ^ { 2 } } { 6 \pi } \mathrm { Nm }

B

1046πNm\frac { 10 ^ { 4 } } { 6 \pi } \mathrm { Nm }

C

1066πNm\frac { 10 ^ { 6 } } { 6 \pi } \mathrm { Nm }

D

1086πNm\frac { 10 ^ { 8 } } { 6 \pi } \mathrm { Nm }

Answer

1046πNm\frac { 10 ^ { 4 } } { 6 \pi } \mathrm { Nm }

Explanation

Solution

Here, P = 100 kW = 100 × 10310 ^ { 3 } W = 105 W10 ^ { 5 } \mathrm {~W}

As