Question

An automobile engine develops 100 kW when rotating at a speed of 1800 rev/min. What torque does it deliver

• A. 350 N-m
• B. 440 N-m
• C. 531 N-m
• D. 628 N-m

Answer 1

Answer: (C)

531 N-m

Answer 2

$P = \tau\omega$ ⇒ $\tau = \frac{100 \times 10^{3}}{2\pi\frac{1800}{60}} = 531N ⥂ \text{- }m$