Question

An atomic power reactor furnace can deliver 300 MW. The energy released due to fission of each of uranium atom $U^{238}$ is 170 MeV. The number of uranium atoms fissioned per hour will be

• A. 5 × 10¹⁵
• B. 10 × 10²⁰
• C. 40 × 10²¹
• D. 30 × 10²⁵

Answer 1

Answer: (C)

40 × 10²¹

Answer 2

By using $P = \frac{W}{t} = \frac{n \times E}{t}$ where n = Number of uranium atom fissioned and E = Energy released due to each fission so $300 \times 10^{6} = \frac{n \times 170 \times 10^{6} \times 1.6 \times 10^{- 19}}{3600}$ ⇒ n = 40 × 10²¹