Question

An atom of an element $A$ has three electrons in its outermost orbit and that of $B$ has six electrons in its outermost orbit. The formula of the compound between these two will be

• A. $A_3 B_6$
• B. $A_2 B_3$
• C. $A_3 B_2$
• D. $A_2 B$

Answer 1

Answer: (B)

$A_2 B_3$

Answer 2

$A$ has three electrons in its outermost orbit, it valency is 3 $B$ has six electrons in its outermost orbit, it valency $=2$ formula of the compound $= A_2B_3$