Question

An athelete is given 100 g of glucose (C6H12O6) of energy equivalent to 1560 kJ. He utilises 50 percent of this gained energy in the event. In order to avoid storage of energy in the body, the weight of water he would need to perspire is- (The enthalpy of evaporation of water is 44 kJ/mole.)

• A. 319 gm
• B. 422 gm
• C. 293 gm
• D. 378 gm

Answer 1

Answer: (A)

319 gm

Answer 2

Given energy = 1560 kJ

Utilised energy = $\frac{1560 \times 50}{100}$ = 780 kJ

44 kJ Utilised energy for evaporation of H2O = 18 gram

$\therefore$ 780 kJ Utilised energy for evaporation of H2O

=$\frac{18}{44}$× 780 = 319 gm