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Question

Physics Question on Motion in a plane

An artillery piece which consistently shoots its shells with the same muzzle speed has a maximum range RR . To hit a target which is R2\frac{R}{2} from the gun and on the same level, the angle of elevation of the gun should be

A

1515^\circ

B

4545^\circ

C

3030^\circ

D

6060^\circ

Answer

1515^\circ

Explanation

Solution

Rmax=R=u2g\text{R}_{\text{max}} = \text{R} = \frac{\text{u}^{2}}{\text{g}} (at an angle of 4545^\circ u2=Rg\text{u}^{2} = \text{Rg} Using Range=u2sin2θg\text{Range} = \frac{\text{u}^{2} \text{sin} 2 \theta }{\text{g}} then R2=(Rg)sin2θg\frac{\text{R}}{2} = \left(\text{Rg}\right) \frac{\text{sin} 2 \theta }{\text{g}} sin2θ=12\text{sin} 2 \theta = \frac{1}{2} 2θ=30o?θ=15o2 \theta = 3 0^{\text{o}} \, \, \, ? \, \, \, \theta = 1 5^{\text{o}}