Question

An artificial radioactive decay series begins with unstable ${}_{94}^{241}Pu$. The stable nuclide obtained after eight a - decays and five b - decays is-

• A. ${}_{83}^{209}Bi$
• B. ${}_{82}^{209}Pb$
• C. ${}_{82}^{205}Ti$
• D. ${}_{82}^{201}Hg$

Answer 1

Answer: (A)

${}_{83}^{209}Bi$

Answer 2

Z = 94 – 16 + 5 = 83

A = 241 – 32 + 0 = 209