Question

An aromatic compound $A (C_7H_9N)$ on reacting with $NaNO_2/HCl$ at $0^\circ\,C$ forms benzyl alcohol and nitrogen gas. The number of isomers possible for the compound $'A'$ is

• A. 7
• B. 6
• C. 5
• D. 3

Answer 1

Answer: (C)

5

Answer 2

Compound $A\left( C _{7} H _{9} N \right)$ is benzyl amine $\left( C _{6} H _{5} CH _{2} NH _{2}\right) .$ It reacts with $NaNO _{2} / HCl$ at $0^{\circ} C$ to form benzyl alcohol and $N _{2}$ gas.

Benzyl amine show s following five isomers.