Question

An army vehicle of mass 1000 kg is moving with a velocity of 10 m/s and is acted upon by a forward force of 1000 N due to the engine and a retarding force of 500 N due to friction. What will be its velocity after 10 s

• A. 5 m/s
• B. 10 m/s
• C. 15 m/s
• D. 20 m/s

Answer 1

Answer: (C)

15 m/s

Answer 2

$v = u + \frac{F}{m}t = 10 + \left( \frac{1000 - 500}{1000} \right) \times 10 = 15m/s$