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Question: An area of cross-section of rubber string is \(2 \mathrm {~cm} ^ { 2 }\). Its length is doubled when...

An area of cross-section of rubber string is 2 cm22 \mathrm {~cm} ^ { 2 }. Its length is doubled when stretched with a linear force of 2×1052 \times 10 ^ { 5 }dynes. The Young's modulus of the rubber in will be

A

4×1054 \times 10 ^ { 5 }

B

1×1051 \times 10 ^ { 5 }

C

2×1052 \times 10 ^ { 5 }

D

1×1041 \times 10 ^ { 4 }

Answer

1×1051 \times 10 ^ { 5 }

Explanation

Solution

If length of the wire is doubled then strain = 1

∴ Y = Stress = Force  Area = \frac { \text { Force } } { \text { Area } }=