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Question

Chemistry Question on Some basic concepts of chemistry

An aqueous solution of oxalic acid dihydrate contains its 6.3 g in 250 ml. The volume of 0.1 N NaOH required to completely neutralize 10 ml of this solution

A

4ml

B

20ml

C

2ml

D

40ml

Answer

40ml

Explanation

Solution

Normality of oxalic add solution =6.3×100063×250=0.4N= \frac{6.3\times1000}{63 \times 250} = 0.4\,N Now from N1V1=N2V2N_{1}V_{1} = N_{2}V_{2} 0.4×10=0.1×V20.4 \times 10 = 0.1 \times V_{2} V2=40mLV_{2}= 40 \,mL