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Question

Chemistry Question on Solutions

An aqueous solution of glucose was prepared by dissolving 18 g of glucose in 90 g of water. The relative lowering in vapour pressure is

A

0.02

B

1.1

C

20

D

196

Answer

0.02

Explanation

Solution

ΔPp=18×18180×90=0.02\frac{ \Delta P}{p^\circ} = \frac{ 18 \times 18}{180 \times 90} = 0.02