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Question

Chemistry Question on Equilibrium Constant

An aqueous solution of glucose is 10%10\% in strength. The volume in which 1g1 \,g mole of it is dissolved will be

A

18 L

B

9L

C

0.9 L

D

1.8 L

Answer

1.8 L

Explanation

Solution

10%10 \% glucose solution means 10g10 \,g =10180=\frac{10}{180} mole in 100cc100 \,cc ie, 0.1L 0.1 \,L Hence, 11 mole of glucose will present in =0.1×18010=1.8L=\frac{0.1 \times 180}{10}=1.8\, L