Solveeit Logo

Question

Question: An aqueous solution of A gives yellow precipitate with \(K_2Cr_2O_4\). A may contain A.\(P{b^{2 + ...

An aqueous solution of A gives yellow precipitate with K2Cr2O4K_2Cr_2O_4. A may contain
A.Pb2+P{b^{2 + }} or Ag+A{g^ + } or Ba2+B{a^{2 + }}
B.Pb2+P{b^{2 + }}or Ba2+B{a^{2 + }}
C.Ag+A{g^ + } or Ba2+B{a^{2 + }}
D.Pb2+P{b^{2 + }} or Ag+A{g^ + }

Explanation

Solution

The inorganic ions are categorized into different groups for their qualitative analysis. Inorganic salts consist of two parts known as radicals. The positively charged part (cation) is called a basic radical and the negatively charged part of the salt (anion) is called an acidic radical.

Complete step by step answer:
-Qualitative analysis involves the identification of cations and anions which are present in the salt or a mixture of salts. In this type of analysis we try to find out the nature of substance and the identity of the constituents.
-Inorganic qualitative analysis mainly involves the identification of cations and anions with the help of various reagents. The cations are mainly categorized into six different groups. There is systematic analysis.
-Potassium chromate left(K2CrO4right)left( {{K_2}Cr{O_4}} right) is used to detect the presence of Pb2+P{b^{2 + }} and [B{a^{2 + }}]ions.
-In the first group lead is precipitated as lead chloride. On adding a potassium chromate solution, a yellow precipitate of lead chromate is obtained. This confirms the presence of lead ions.
PbCl2+K2CrO4PbCrO4+2KClPbC{l_2}\, + \,{K_2}Cr{O_4} \to PbCr{O_4}\, + \,2KCl
-The group five cations are precipitated as their carbonates which dissolve in acetic acid due to the formation of corresponding acetates.
-Potassium chromate solution gives a yellow precipitate of barium carbonate when the solution of fifth group precipitate in acetic acid is treated with it.
BaCO3+CH3COOH(CH3COOH)2Ba+H2O+CO2BaC{O_3}\, + \,C{H_3}COOH\, \to {(C{H_3}COOH)_2}Ba\, + \,{H_2}O\, + \,C{O_2}
(CH3COO)2Ba+K2CrO4BaCrO4+2CH3COOK{(C{H_3}COO)_2}Ba\, + \,{K_2}Cr{O_4}\, \to BaCr{O_4}\, + \,2C{H_3}COOK
-So we can see that lead and barium ions are detected with the help of potassium chromate solution.
Hence the correct option is B.

Note:
-The structure of potassium chromate is


-Potassium chromate is a water-soluble compound. It appears as a yellow crystalline solid. Its mineral form is called tarapacaite.