Question

An aqueous solution of $6.3\, g$ oxalic acid dehydrate is made upto $250\, mL$. The volume of $0.1N\, NaOH$ required to completely neutralize $10 \,ml$. of this solution is

• A. $40 \,mL$
• B. $20\, mL$
• C. $10\, mL$
• D. $4 \,mL$

Answer 1

Answer: (A)

$40 \,mL$

Answer 2

Oxalic acid dihydrate $H_2C_2O_4.2H_2O:mw=126$
It is a dibasic acid, hence equivalent weight = 63
$\Rightarrow \, \, \, \, \, \, \, \, \, \, \, \, \, Normality=\frac{6.3}{63}\times \frac{1000}{250}=0.4 N$
$\Rightarrow \, \, \, \, \, \, \, \, \, \, \, \, \, N_1V_1 =N_2V_2$
$\Rightarrow \, \, \, \, \, \, \, \, \, \, \, \, 0.1 \times V_1 =0.4 \times \, 10$
Hence, $\, \, \, \, \, \, \, \, \, \, \, \, V_1 =40 mL$