Question

An aqueous solution of 6.3 g of oxalic acid dihydrate is made upto 250 mL. The volume of $\text{0}\text{.1}\,\text{N}\,\text{NaOH}$ required to completely neutralize 10 mL of this solution is

• A. $\text{40 mL}$
• B. $\text{20 mL}$
• C. $10\,mL$
• D. $4\,mL$

Answer 1

Answer: (A)

$\text{40 mL}$

Answer 2

Equivalent weight of oxalic acid $=126/2$
( $\because$ Basicity of oxalic acid $=2$ )
Normality of oxalic acid solution
$=\frac{6.3\times 1000}{63\times 250}$
$=0.4\,N$ $\underset{(Acid)}{\mathop{{{N}_{1}}{{V}_{1}}}}\,=\underset{(Base)}{\mathop{{{N}_{2}}{{V}_{2}}}}\,$
$0.4\times 10\,mL=0.1\times {{V}_{2}}$
${{V}_{2}}=40\,mL$