Question
Question: An aqueous solution containing one mole of \(Hg{I_2}\) and two moles of \(NaI\) is orange in colour....
An aqueous solution containing one mole of HgI2 and two moles of NaI is orange in colour. In addition to excess NaI, the solution becomes colourless. The orange colour reappears on the subsequent addition of NaOCl.
If the statement is true enter 1 else enter 0.
Solution
Sodium Iodide is an ionic compound formed by the chemical reaction of sodium metal and iodine comprising a 1:1 mix of sodium cations (Na+) and iodide ions (I−) in a crystal lattice. NaI is a white odourless crystal or powder with a melting point of 651∘C and has a boiling point of 1304∘C. NaI is a deliquescent solid which absorbs moisture and turns into a solution. It is also a weak reducing agent. Sodium iodide is very soluble in water and some organic solvents.
Complete step by step answer:
As we know the colour of sodium iodide is white and the colour HgI2 is orange. If we prepare an aqueous solution containing one mole of HgI2 and two moles of NaI, then the orange colour compound is formed. If we add NaI in excess, HgI2 is consumed completely, i.e. it is a limiting reagent. Hence the resulting solution becomes colourless due to formation of colourless NaHgI4. The chemical reaction of HgI2 with excess of NaI is given as:
2NaI+HgI2→NaHgI4
When we add sodium hypochlorite NaOCl subsequently in the above solution, due to regeneration of HgI2, orange colour reappears. The chemical reaction for above is given below:
Na2HgI4+NaOCl+H2O→2NaOH+NaCl+HgI2+I2
Hence the statement is true so press 1.
Note:
Sodium hypochlorite(NaOCl) is a salt formed by the combination of negatively charged hypochlorite ion (ClO−) and a positively charged sodium ion (Na+). Hypochlorite decomposes to yield a variety of by-products in a solution. Hypochlorous acid which is a by-product of Hypochlorite acts as a powerful oxidizing agent and due to this hypochlorite exhibits the excellent ability of bleaching and disinfecting.