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Question: An aqueous solution containing one mole of \(Hg{I_2}\) and two moles of \(NaI\) is orange in colour....

An aqueous solution containing one mole of HgI2Hg{I_2} and two moles of NaINaI is orange in colour. In addition to excess NaINaI, the solution becomes colourless. The orange colour reappears on the subsequent addition of NaOClNaOCl.
If the statement is true enter 1 else enter 0.

Explanation

Solution

Sodium Iodide is an ionic compound formed by the chemical reaction of sodium metal and iodine comprising a 1:1 mix of sodium cations (Na+)\left( {N{a^ + }} \right) and iodide ions (I)\left( {{I^ - }} \right) in a crystal lattice. NaINaI is a white odourless crystal or powder with a melting point of 651C{651^\circ }C and has a boiling point of 1304C{1304^\circ }C. NaINaI is a deliquescent solid which absorbs moisture and turns into a solution. It is also a weak reducing agent. Sodium iodide is very soluble in water and some organic solvents.

Complete step by step answer:
As we know the colour of sodium iodide is white and the colour HgI2Hg{I_2} is orange. If we prepare an aqueous solution containing one mole of HgI2Hg{I_2} and two moles of NaINaI, then the orange colour compound is formed. If we add NaINaI in excess, HgI2Hg{I_2} is consumed completely, i.e. it is a limiting reagent. Hence the resulting solution becomes colourless due to formation of colourless NaHgI4NaHg{I_4}. The chemical reaction of HgI2Hg{I_2} with excess of NaINaI is given as:
2NaI+HgI2NaHgI42NaI + Hg{I_2} \to NaHg{I_4}
When we add sodium hypochlorite NaOClNaOCl subsequently in the above solution, due to regeneration of HgI2Hg{I_2}, orange colour reappears. The chemical reaction for above is given below:
Na2HgI4+NaOCl+H2O2NaOH+NaCl+HgI2+I2N{a_2}Hg{I_4} + NaOCl + {H_2}O \to 2NaOH + NaCl + Hg{I_2} + {I_2}
Hence the statement is true so press 1.

Note:
Sodium hypochlorite(NaOCl)\left( {NaOCl} \right) is a salt formed by the combination of negatively charged hypochlorite ion (ClO)(Cl{O^ - }) and a positively charged sodium ion (Na+)\left( {N{a^ + }} \right). Hypochlorite decomposes to yield a variety of by-products in a solution. Hypochlorous acid which is a by-product of Hypochlorite acts as a powerful oxidizing agent and due to this hypochlorite exhibits the excellent ability of bleaching and disinfecting.