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Question: An an atom which has \(2\)K, \(8\)L, \(16\)M and\(2\)N electrons in the group the total no, of elect...

An an atom which has 22K, 88L, 1616M and22N electrons in the group the total no, of electrons having l = 1{\text{l}}\,{\text{ = }}\,{\text{1}} are:
A.2020
B.88
C.1212
D.1212

Explanation

Solution

To answer this question we should know what K, L, M, and N and l = 1{\text{l}}\,{\text{ = }}\,{\text{1}}represents. So, we should have knowledge of quantum numbers. First we will write the electronic configuration from the given information. Then we will count the electrons having l = 1{\text{l}}\,{\text{ = }}\,{\text{1}}.

Complete solution:
Electronic configuration of an atom has four quantum numbers.
Principle quantum number: it tells the energy level or shell.
Its value ranges from 11 - \infty .
The name of energy level is given by alphabets which are shown as follows:

Energy levelName of the level
1K
2L
3M
4N

Azimuthal quantum number: it tells the orbital.
Its value ranges from 0(n1)0 - ({\text{n}} - 1).
Magnetic quantum number: It tells the orbital of the subshell.
Its value ranges from (l)( + l)( - {\text{l)}}\, - ({\text{ + l}}).
It is determined by 2l + 1{\text{2l}}\,{\text{ + }}\,{\text{1}}.
Spin quantum number: It tells the spin of an electron.
Its value is 1/2 - 1/2 or +1/2 + 1/2.
Now, we will write the electronic configuration from the given information as follows:
22K, means K-shell has two electrons in s-orbital, 88L means L-shell has eight electrons, two in s and six in p-orbital, 1616M means M-shell has sixteen electrons, two in s, six in p and eight in d-orbital, and22N means N-shell has two electrons is s-orbital.
Now, we have to find the electrons having l = 1{\text{l}}\,{\text{ = }}\,{\text{1}}, l = 1{\text{l}}\,{\text{ = }}\,{\text{1}} means p-orbital. From the above electronic configuration we can tell that six electrons are present in 22p-orbital of L-shell and six electrons are present in 33p-orbital of M-shell.
So, a total of twelve electrons are present in l = 1{\text{l}}\,{\text{ = }}\,{\text{1}}.
So, the total no, of electrons having l = 1{\text{l}}\,{\text{ = }}\,{\text{1}} are 1212.

Therefore, option (C) and (D) 1212 both are correct.

Note: The number of energy levels represents the number of orbital present in it such as energy level one that is K has one orbital only that is s-orbital. Similarly, energy level two that is L-shell has two orbitals s and p. the number of maximum electrons in a shell is determined by 2n2{\text{2}}{{\text{n}}^{\text{2}}} . Where n is the number of energy levels. We can also determine the number of electrons having l = 0{\text{l}}\,{\text{ = }}\,0 and l = 2{\text{l}}\,{\text{ = }}\,2.