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Question

Physics Question on communication systems

An amplitude modulated wave is represented by the expression vm=5(1+0.6cos6280t)v _{ m }=5(1+0.6 \cos 6280 t ) sin(211×104t)\sin \left(211 \times 10^{4} t \right) volts. The minimum and maximum amplitudes of the amplitude modulated wave are, respectively :

A

5V,8V5 V , 8 V

B

32V,5V\frac{3}{2} V , 5 V

C

52V,8V\frac{5}{2} V , 8 V

D

3V,5V3 V , 5 V

Answer

52V,8V\frac{5}{2} V , 8 V

Explanation

Solution

Vm=5(1+0.6cos6280t)sin(211×104t)V _{ m }=5(1+0.6 \cos 6280 t ) \sin \left(211 \times 10^{4} t \right)
Vm=[5+3cos6820t]sin(211×104t)V _{ m }=[5+3 \cos 6820 t ] \sin \left(211 \times 10^{4} t \right)
Vmax=5+3=8V _{\max }=5+3=8
Vmin. =53=2V _{\text {min. }}=5-3=2