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Question: An ammeter reads upto 1 ampere. Its internal resistance is 0.81 ohm. To increase the range to 10 A, ...

An ammeter reads upto 1 ampere. Its internal resistance is 0.81 ohm. To increase the range to 10 A, the value of the required shunt is
A) 0.03Ω0.03\Omega
B) 0.3Ω0.3\Omega
C) 0.9Ω0.9\Omega
D) 0.09Ω0.09\Omega

Explanation

Solution

Hint: A shunt is connected parallel to an ammeter in order to enable the ammeter to measure higher currents. So the shunt that is being connected should have a resistance that will allow the ammeter to measure a particular current range.

Complete step by step answer:

In the problem, it is given that the internal resistance of the ammeter is 0.81Ω0.81\Omega and the max current the ammeter can read is 1 ampere. We need to increase this 1 ampere range to 10 A. In order to do that we need to connect a shunt parallel to the ammeter.
Let I\text{I} be the maximum current in the range we need to set and ig{{i}_{g}} be the current flowing through the ammeter. So the current flowing through the shunt is given by IigI-{{i}_{g}}.
Since the ammeter is connected in parallel with the shunt, the voltage drop across each of them is same, so we can write,
IshRsh=IamRam{{\text{I}}_{\text{sh}}}{{\text{R}}_{\text{sh}}}={{\text{I}}_{\text{am}}}{{\text{R}}_{\text{am}}}
Ish{{\text{I}}_{\text{sh}}} is the current across the shunt. We have calculated it as IigI-{{i}_{g}}.
Rsh{{\text{R}}_{\text{sh}}} is the resistance of the shunt. Which we need to find out.
Iam{{\text{I}}_{am}} is the current across the ammeter. We have taken it as ig{{i}_{g}}.
Ram{{\text{R}}_{am}} is the internal resistance of the ammeter.
So the resistance of the shunt can be written as,
Rsh=IamRamIsh=igRam(Iig){{R}_{sh}}=\dfrac{{{I}_{am}}{{R}_{am}}}{{{I}_{sh}}}=\dfrac{{{i}_{g}}{{R}_{am}}}{\left( I-{{i}_{g}} \right)}
Substituting the values of ig{{i}_{g}},Iam{{\text{I}}_{am}},Ram{{\text{R}}_{am}} we get,
Rsh=1A×0.81Ω(10A1A){{R}_{sh}}=\dfrac{1A\times 0.81\Omega }{\left( 10A-1A \right)}
Rsh=0.09Ω{{R}_{sh}}=0.09\Omega

Note:
In the absence of a shunt, higher current can damage an ammeter which is supposed to measure low currents. Higher currents can produce the heating effect, which will result in the burning of the ammeter coil.
A shunt provides a low resistance path for the current to flow. For proper working, the resistance of the shunt should not change with temperature.