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Question

Physics Question on Current electricity

An ammeter reads upto 11 ampere. Its internal resistance is 0.81ohm0.81\, ohm. To increase the range to 10A10\, A the value of the required shunt is

A

0.03O0.03\, O

B

0.3O0.3\, O

C

0.9O0.9\, O

D

0.09O0.09\, O

Answer

0.09O0.09\, O

Explanation

Solution

S=IgGIIg=1×0.81101=0.09OS=\frac{I_{g}G}{I-I_{g}}=\frac{1\times0.81}{10-1}=0.09\, O