Question

An ammeter of 5 ohm resistance can read 5 mA. If it is to be used to read 100 volts, how much resistance is to be connected in series

• A. $19.9995\Omega$
• B. $199.995\Omega$
• C. $1999.95\Omega$
• D. $19995\Omega$

Answer 1

Answer: (D)

$19995\Omega$

Answer 2

By using $R = \frac{V}{I_{g}} - G$ ⇒ $R = \frac{100}{5 \times 10^{- 3}} - 5 = 19,995\Omega$