Question

An AM wave has 1800 watt of total power content, For 100% modulation the carrier should have power content equal to

• A. 1000 watt
• B. 1200 watt
• C. 1500 watt
• D. 1600 watt

Answer 1

Answer: (B)

1200 watt

Answer 2

$P_{t} = P_{c}\left( 1 + \frac{m_{a}^{2}}{2} \right);$ Here m_a = 1

⇒ $1800 = P_{c}\left( 1 + \frac{(1)^{2}}{2} \right)$ ⇒ $P_{c} = 1200W$