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Question

Physics Question on Alternating current

An alternating voltage of amplitude 40 V and frequency 4 kHz is applied directly across the capacitor of 12 μF. The maximum displacement current between the plates of the capacitor is nearly:

A

13 A

B

8 A

C

10 A

D

12 A

Answer

12 A

Explanation

Solution

The displacement current in a capacitor is the same as the conduction current. The capacitive reactance XcX_c is given by:

Xc=1ωC=12πfCX_c = \frac{1}{\omega C} = \frac{1}{2 \pi f C}

Substituting the given values:

Xc=12π×4×103Hz×12×106F3.317ΩX_c = \frac{1}{2 \pi \times 4 \times 10^3 \, \text{Hz} \times 12 \times 10^{-6} \, \text{F}} \approx 3.317 \, \Omega

The current II is given by:

I=VXc=40V3.317Ω12AI = \frac{V}{X_c} = \frac{40 \, \text{V}}{3.317 \, \Omega} \approx 12 \, \text{A}