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Question

Physics Question on AC Voltage

An alternating voltage of 220 V, 50 Hz frequency is applied across a capacitor of capacitance 2 μ\muF. The impedence of the circuit is

A

π5000\frac{\pi}{5000}

B

1000π\frac{1000}{\pi}

C

500π500 \pi

D

5000π\frac{5000}{\pi}

Answer

5000π\frac{5000}{\pi}

Explanation

Solution

Impedence of a capacitor is XC=1/ωCX_{C}=1/ \omega C
XC=12πfC=12π×50×2×106=5000π.X_{C}=\frac{1}{2 \pi f C}=\frac{1}{2 \pi\times50\times2\times10^{-6}} =\frac{5000}{\pi} .