Question

An alternating voltage given by V = 140 sin 314 t is connected across a pure resistor of$50\Omega$ the rms current through the resistor is

• A. 1.98 A
• B. 5.63 A
• C. 8.43 A
• D. 2.39 A

Answer 1

Answer: (A)

1.98 A

Answer 2

Here, ,$R = 50\Omega,V_{0} = 140V$

$\therefore I_{rms} = \frac{V_{rsm}}{R} = \frac{0.707V_{0}}{R}$

$= \frac{0.707 \times 140}{50}$

$= 1.98A.$