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Question: An alternating voltage \(E = 200\sqrt{2}\sin(100t)\) is connected to a 1 microfarad capacitor throug...

An alternating voltage E=2002sin⁡(100t)E = 200\sqrt{2}\sin(100t) is connected to a 1 microfarad capacitor through an ac ammeter. The reading of the ammeter shall b

A

10 mA

B

20 mA

C

40 mA

D

80 mA

Answer

20 mA

Explanation

Solution

Reading of ammeter

=irms=VrmsXC=V0ωC2= i_{rms} = \frac{V_{rms}}{X_{C}} = \frac{V_{0}\omega C}{\sqrt{2}}

=2002×100×(1×10−6)2=2×10−2A=20 6mumA= \frac{200\sqrt{2} \times 100 \times (1 \times 10^{- 6})}{\sqrt{2}} = 2 \times 10^{- 2}A = 20\mspace{6mu} mA