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Question: An alternating voltage \(E = 200\sqrt{2}\sin(100t)\) is connected to a 1 microfaracd capacitor throu...

An alternating voltage E=2002sin⁡(100t)E = 200\sqrt{2}\sin(100t) is connected to a 1 microfaracd capacitor through an ac ammeter. The reading of the ammeter shall be

A

10 mA

B

20 mA

C

40 mA

D

80 mA

Answer

20 mA

Explanation

Solution

Ammeter reads r.m.s. value so irms=VrmsXC=Vrms×ω×Ci_{rms} = \frac{V_{rms}}{X_{C}} = V_{rms} \times \omega \times C ⇒ irms=(20022)×100×(1×10−6)=2×10−2=20mA.i_{rms} = \left( \frac{200\sqrt{2}}{\sqrt{2}} \right) \times 100 \times (1 \times 10^{- 6}) = 2 \times 10^{- 2} = 20mA.