Question

An alternating voltage E = 200$\sqrt { 2 }$sin (100 t) V is connected to a 1mF capacitor through an ac ammeter. The reading of ammeter will be-

• A. 10 mA
• B. 50 mA
• C. 20 mA
• D. 40 mA

Answer 1

Answer: (C)

20 mA

Answer 2

E₀ = 200$\sqrt { 2 }$V and w = 100 rad./s

So X_c = $\frac { 1 } { 100 \times 10 ^ { - 6 } }$ = 10⁴W

As ammeter reads rms value of current

\ I_rms = =

= $\frac { 200 \sqrt { 2 } } { \sqrt { 2 } \times 10 ^ { 4 } }$

= 20 mA