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Question: An alternating supply of 220 V is applied across a circuit with resistance 22\(\Omega\) and impedanc...

An alternating supply of 220 V is applied across a circuit with resistance 22Ω\Omega and impedance 44Ω\Omega.The power dissipated in the circuit is

A

1100W

B

550W

C

2200w

D

(2200/3) W

Answer

550W

Explanation

Solution

: Here, V=220VV = 220V

Resistance, R=22ΩR = 22\Omega

Impedance, Z=44ΩZ = 44\Omega

Current in circuit, I=VZ=22044Ω=5AI = \frac{V}{Z} = \frac{220}{44\Omega} = 5A

Power dissipated in the circuit,

P=I2R=(5)2×22=550WP = I^{2}R = (5)^{2} \times 22 = 550W