Question
Question: An alternating supply of 220 V is applied across a circuit with resistance 22\(\Omega\) and impedanc...
An alternating supply of 220 V is applied across a circuit with resistance 22Ω and impedance 44Ω.The power dissipated in the circuit is
A
1100W
B
550W
C
2200w
D
(2200/3) W
Answer
550W
Explanation
Solution
: Here, V=220V
Resistance, R=22Ω
Impedance, Z=44Ω
Current in circuit, I=ZV=44Ω220=5A
Power dissipated in the circuit,
P=I2R=(5)2×22=550W