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Question

Physics Question on Alternating current

An alternating supply of 220V220\,V is applied across a circuit with resistance 22Ω22\,\Omega and impedance 44Ω44\,\Omega. The power dissipated in the circuit is

A

1100W1100\,W

B

550W550\,W

C

2200W2200\,W

D

(2200/3)W(2200/3)\,W

Answer

550W550\,W

Explanation

Solution

Here, V=220VV= 220\,V Resistance, R=22ΩR = 22\,\Omega Impedance, Z=44ΩZ = 44\,\Omega Current in circuit, I=VZI=\frac{V}{Z} =220V44Ω=\frac{220\,V}{44\,\Omega} =5A= 5\,A Power dissipated in the circuit, P=I2R=(5)2×22P=I^{2}R=\left(5\right)^{2}\times22 =550W=550\,W