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Question: An alternating e.m.f. is applied to purely capacitive circuit. The phase relation between e.m.f. and...

An alternating e.m.f. is applied to purely capacitive circuit. The phase relation between e.m.f. and current flowing in the circuit is

Or

In a circuit containing capacitance only

A

e.m.f. is ahead of current by π / 2

B

Current is ahead of e.m.f. by π / 2

C

Current lags behind e.m.f. by π

D

Current is ahead of e.m.f. by π

Answer

Current is ahead of e.m.f. by π / 2

Explanation

Solution

For purely capacitive circuit e=e0sinωte = e _ { 0 } \sin \omega t

i=iosin(ωt+π2)i = i _ { o } \sin \left( \omega t + \frac { \pi } { 2 } \right) i.e. current is ahead of emf by π2\frac { \pi } { 2 }