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Question

Physics Question on Alternating current

An alternating current is given by I=I1cosωt+I2sinωtI = I _{1} \cos \omega t +I_{2} \sin \omega t, the root mean square current is given by

A

I1+I22\frac{I_{1}+I_{2}}{\sqrt{2}}

B

I1+I22\frac{\left|I_{1}+I_{2}\right|}{2}

C

I12+I222\sqrt{\frac{I_{1}^{2}+I_{2}^{2}}{2}}

D

I12+I222\sqrt{\frac{I_{1}^{2}+I_{2}^{2}}{2}}

Answer

I12+I222\sqrt{\frac{I_{1}^{2}+I_{2}^{2}}{2}}

Explanation

Solution

The equation of alternating current (AC) is given by I=I1cosωt+I2sinωtI=I_{1} \cos \omega t+I_{2} \sin \omega t The resultant current I0=I12+I22I_{0}=\sqrt{I_{1}{ }^{2}+I_{2}{ }^{2}} Also, rmsrms value of current is given by Irms=I02I_{ rms } =\frac{I_{0}}{\sqrt{2}} Irms=I12+I222\Rightarrow I_{ rms } =\sqrt{\frac{I_{1}{ }^{2}+I_{2}{ }^{2}}{2}}