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Question: An alpha particle of 10 MeV collides head-on with a copper nucleus (Z = 29) and is deflected back. T...

An alpha particle of 10 MeV collides head-on with a copper nucleus (Z = 29) and is deflected back. Then the minimum distance of approach between the centres of the two is –

A

8.4 × 10–15 cm

B

8.4 × 10–15 m

C

4.2 × 10–15 m

D

4.2 × 10–15 cm

Answer

8.4 × 10–15 m

Explanation

Solution

r0 = 2KZe2E\frac{2KZe^{2}}{E}