Question

An alpha particle is accelerated through a potential difference of $10^{6}volt$. Its kinetic energy will be

• A. $1MeV$
• B. $2MeV$
• C. $4MeV$
• D. $8MeV$

Answer 1

Answer: (B)

$2MeV$

Answer 2

$K = qV = 2e \times 10^{6}J = \frac{2e \times 10^{6}}{e}eV = 2MeV$