Solveeit Logo

Question

Physics Question on Nuclear physics

An alpha particle (He)has a mass of 4.00300 amu. A proton has mass of 1.00783 amu and a neutron has mass of 1.00867 amu respectively. The binding energy of alpha particle estimated from these data is the closest to

A

27.9 MeV

B

22.3 MeV

C

35.0 MeV

D

20.4 MeV

Answer

27.9 MeV

Explanation

Solution

The mass defect, Δm=2(mp+mn)mHe\Delta m=2\left(m_{p}+m_{n}\right)-m_{ He }
=2(1.00783+1.00867)4.00300=2(1.00783+1.00867)-4.00300
=0.0300=0.0300 amu
So, the binding energy, E=Δmc2E=\Delta m c^{2}
=0.03×931MeV27.9MeV=0.03 \times 931 MeV \approx 27.9 \,MeV