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Question: An alkyl halide X reacts with sodium to form 3,8-dimethyldecane. What is X?...

An alkyl halide X reacts with sodium to form 3,8-dimethyldecane. What is X?

A

CH3CH2−CH∣CH3−CH2CH2ClCH_{3}CH_{2} - \underset{CH_{3}}{\underset{|}{CH}} - CH_{2}CH_{2}Cl

B

CH3CH2CH2CH2ClCH_{3}CH_{2}CH_{2}CH_{2}Cl

C

CH3−C∣H∣CH3−C∣∣CH3H−CH2−CH2−CH2−CH2ClCH_{3} - \overset{CH_{3}}{\overset{|}{\underset{H}{\underset{|}{C}}}} - \overset{H}{\underset{CH_{3}}{\overset{|}{\underset{|}{C}}}} - CH_{2} - CH_{2} - CH_{2} - CH_{2}Cl

D

CH3−C∣CH3∣CH3−CH2CH2ClCH_{3} - \underset{}{\overset{CH_{3}}{\overset{|}{\underset{\underset{CH_{3}}{|}}{C}}} - CH_{2}CH_{2}Cl}

Answer

CH3CH2−CH∣CH3−CH2CH2ClCH_{3}CH_{2} - \underset{CH_{3}}{\underset{|}{CH}} - CH_{2}CH_{2}Cl

Explanation

Solution

: In Wurtz reaction, two molecules of RCl combine to give R-R 3,8-Dimethyldecane can be formed by combining two molecules of

CH3−CH2−CH∣CH3−CH2−CH2ClCH_{3} - CH_{2} - \underset{CH_{3}}{\underset{|}{CH}} - CH_{2} - CH_{2}Cl

I- chloro-3- methylpentane