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Chemistry Question on Amines

An alkyl cyanide forms an amide when it is treated with

A

H2O+HClH_2O + HCl

B

NaOH+H2ONaOH + H_2O

C

H2O2+NaOHH_2O_2 + NaOH

D

H2SO4+H2OH_2SO_4 + H_2O

Answer

H2SO4+H2OH_2SO_4 + H_2O

Explanation

Solution

Amides are produced by alkyl cyanides by shaking them with cold cone. HClHCl or by dissolving the nitriles in cone. H2SO4H_2SO_4 and then pouring them into water.
R−C≡N+H2Oalkyl cyanide−>[Cold conc.HCl]R−CO∣∣−NH2amide\underset{\text{alkyl cyanide}}{R - C \equiv N + H_2O} {->[\text{Cold conc}. HCl]} \underset {\text{amide}}{R - \overset{\underset{||}{O}}{C} - NH_2}
R−C≡N alkyl cyanide−>[Dissolve in conc.H2SO4][and then pour inH2O]R−CO∣∣−NH3amide\underset{\text{ alkyl cyanide}}{R - C \equiv N} {->[\text{Dissolve in conc.} H_2SO_4][\text{and then pour in} H_2O]} \underset{\text{amide}}{R - \overset{\underset{||}{O}}{C} - NH_3}