Question

An alkene (1) C₁₆H₁₆ on ozonolysis gives only one product (2) (C₈H₈O). Compound (2) on reaction with NH₂OH/H₂SO₄, Dgives N-methyl benzamide. The compound 'A' is -

• A.
• B.
• C.
• D.

Answer 1

Answer: (B)

Answer 2

A $\overset{\quad Ozonolysis\quad}{\rightarrow}$ B $\underset{\Delta}{\overset{\quad NH_{2}OH/H^{+}\quad}{\rightarrow}}$ oxime followed by Beckmann's rearrangement

So B is and A is