Question

An alkali metal hydride $(NaH)$ reacts with diborane in $A$ to give a tetrahedral compound $B$ which is extensively used as reducing agent in organic synthesis. The compounds $A$ and $B$ respectively are

• A. $C_2H_6$ and $C_2H_5Na$
• B. $CH_3COCH_3$ and $B_3N_3H_6$
• C. $C_6H_6$ and $NaBH_4$
• D. $(C_2H_5)_2O$ and $NaBH_4$

Answer 1

Answer: (D)

$(C_2H_5)_2O$ and $NaBH_4$

Answer 2

Sodium hydride NaH reacts with diborane in diethylether to give tetrahydridoborates, i.e. sodium borohydride which is used as reducing agent in organic synthesis. $\underset{\text{Sodmm hydnde }}{{2NaH}} +\underset{\text{Diboran}}{{B_2H_6}} { ->[{Diethyl}][{ether}] A} \underset{\text{Sodium borohydride B}}{{2Na^+[BH_4]^-]}}$ A=diethyl ether $\left( C _{2} H _{5}\right)_{2} O$ B= Sodium borohydride $NaBH _{4}$