Question

An aircraft with a wingspan of $40\, m$ flies with a speed of $1080\, km/hr$ in the eastward direction at a constant altitude in the northern hemisphere, where the vertical component of the earth's magnetic field $1.75 \times 10^{-5}$ $T$. Then the emf developed between the tips of the wings is

• A. 0.5 V
• B. 0.34 V
• C. 0.21 V
• D. 2.1 V

Answer 1

Answer: (C)

0.21 V

Answer 2

Given, $l=40 \,m$
$B_{v} =1.75 \times 10^{-5} \,T$
$v =1080 \,km / h =1080 \times \frac{5}{18} \,m / s$
We know that, emf developed between the tips of the wings,
$e =B_{v} . l v$
$e =40 \times 1.75 \times 10^{-5} \times 1080 \times \frac{5}{18}$
$e =21000 \times 10^{-5}$
$e =0.21 \,V$