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Question

Physics Question on laws of motion

An aircraft executes a horizontal loop at a speed of 720km720\, km h1h^{-1} with its wings banked at 15?15^?. What is the radius of the loop? (Take g=10ms2,tan15=0.27g=10\, m s^{-2}, tan \,15^{\circ}=0.27)

A

14.8km14.8 \, km

B

14.8m14.8\, m

C

29.6km29.6\,km

D

29.6m29.6\, m

Answer

14.8km14.8 \, km

Explanation

Solution

Here, v=720kmv=720 \,km h1h^{-1} =720×518m=720\times\frac{5}{18}m s1s^{-1} =200m=200\, m s1s^{-1} θ=15\theta=15^{\circ}, g=10ms2g=10 \,m s^{-2} As tan θ=v2rg\theta=\frac{v^{2}}{rg} \therefore\quad r=v2tanθg r=\frac{v^{2}}{tan\,\theta\, g} =(200ms1)2tan15×10ms2=\frac{\left(200\, m\, s^{-1}\right)^{2}}{tan\, 15^{\circ}\times10 \,m \,s^{-2}} =14815m=14.8km=14815 \,m=14.8 \,km