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Question: An AIR station is broadcasting the waves of wavelength 300 metres. If the radiating power of the tra...

An AIR station is broadcasting the waves of wavelength 300 metres. If the radiating power of the transmitter is 10 kW, then the number of photons radiated per second is.

A

1.5×10291.5 \times 10^{29}

B

1.5×10311.5 \times 10^{31}

C

1.5×10331.5 \times 10^{33}

D

1.5×10351.5 \times 10^{35}

Answer

1.5×10311.5 \times 10^{31}

Explanation

Solution

P=Wt=nhcλt⇒(nt)=Pλhc=10×103×3006.6×10−34×3×108P = \frac{W}{t} = \frac{nhc}{\lambda t} \Rightarrow \left( \frac{n}{t} \right) = \frac{P\lambda}{hc} = \frac{10 \times 10^{3} \times 300}{6.6 \times 10^{- 34} \times 3 \times 10^{8}}

=1.5×1031= 1.5 \times 10^{31}